BIS 101 General Information

Practice Exam

I did not have a previous sample exam. So I am creating this sample exam and adding questions as they are ready. Come back and check for more questions. It should be complete by Saturday afternoon.

The key is on the next page. Try to understand and answer the question before you look at the key…

Q1. Consider the inheritance problem represented in the table below displaying genotypes and number of individuals produced in a cross. Dominant loci are represented as +. The gene phase (no order implied) is _______ and the gene order (no phase implied) is ________:

m r q	3
m + +	183
+ r +	264
m + q	288
+ + q	1101
+ + +	9
+ r q	138
m r +	1014

A. mr+, m-q-r

B. +rq, q-m-r

C. +r+, r-m-q

D. +++, m-r-q

E. m++, r-m-q

Q2 A and B = chromosomal loci. Dominant and recessive alleles = upper and lower case letters. Parents AABB and aabb are crossed. The hybrid AaBb is crossed to aabb. The following phenotypic classes and progeny numbers are produced: AB, 30; Ab, 450; aB, 410; ab, 35. Allele A is in coupling with allele _____. The best estimate of map distance between the A and B loci is ___ m.u.:

A. a, 3

B. b, 6

C. B, 12

D. a, 24

E. b, 10

Q3 You obtain the sequence for the mRNA transcribed from the actin gene of hammerhead shark. You identify the corresponding DNA template strand in the dsDNA of the actin locus. The 5′ end of the coding strand is closest to this element.

A. terminator

B. promoter

C. intron

D. enhancer

E. centromere

Q4 In a pea plant the A and B genes are linked at 10 m.u. distance. You characterize the pollen grains of this individual. The expected ratio of recombinant:parental gametes for the A-B genes is:

A. 1:19

B. 1:9

C. 1:4.5

D. 1:1

E. 3:1

Q5. An enhancer can cause increased expression of a gene even from which it is separated by as many as 50,000 base pairs because:

A. enhancer encodes a diffusible product that binds promoter

B. of electrical current flow from enhancer to promoter

C. the region in between is transcribed

D. intron splicing removes the DNA between enhancer and promoter

E. enhancer gets close to the promoter by formation of a chromatin loop $

See page 5 for Key
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